Question

can someone please help integrate this? ><

V=2π⋅∫02ex−e−xdx

Answer 1

did in the other question u posted adi ......

Answer 2

-4pi + 2/e^2pi + 2e^2pi

Answer 3

i dont get how you got that gahh sorry ><

Answer 4

\[2\pi \int\limits_{0}^{2}e ^{x}-e ^{-x} dx\]
=\[2\pi(\frac{1}{e ^{2}}+e ^{2}-2)\]

Answer 5

so as of now u just plugged in for you integral of the 2 right? wherever x is?

Answer 6

Substitute 2 and 0 to x into equation, then minus them