Question

tan^2x = cos(150)tan(-330)/sin(150)

Answer 1

We have
\[ \tan ^2x= \cos(150) \times \frac{\tan(-330)}{\sin 150}\]
@meow.fz do you know the value of cos 150, sin 150 and tan (-330)\

Answer 2

cos(150) = -\[\sqrt{3}\div2\]
sin(150) = \[\sqrt{3}\div2\]
tan(-330) = \[1\div \sqrt{3}\]

Answer 3

great but sin 150 is
[\frac{1}{2}\]
no worries, Let's proceed with the problem, let's substitute the values
\[\tan^2 x= \frac{-\sqrt{3}}{2}\frac{ \frac{1}{\sqrt 3}}{\frac{1}{2}} \]
now let's cancel the common terms
\[\tan^2 x= \frac{-\cancel {\sqrt{3}}}{\cancel2}\frac{ \frac{1}{\cancel{\sqrt 3}}}{\frac{1}
{\cancel2}} \]
so we get
\[ \tan^2 x=-1\]
\[=> \tan x= \pm i( i=\sqrt{-1})\]
so no real solution

Answer 4

\[\sin 150=\frac{1}{2}\]

Answer 5

Did you understand?

Answer 6

okay cool ,thank you sooo much dude , i really appreciate it , i have this assignment due tomorrow , and im battling with putting the answers together , thanks , i understood :)

Answer 7

welcome meow:D and Welcome to Open Study:D

Answer 8

thank you :)