Find the limit. limit x-->infinity (e^-2x)*cosx
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Limit as x approaches infinity of e to the negative 2x times cosine x.
We have \[ \lim _{x\to \infty} e^{-2x} \cos x\] now we can write this as \[ \lim _{x\to \infty} \frac{\cos x}{ e^{2x}}\] now as x-> infinity e^{2x}--> infinity we know that cos x has value between -1 and 1, so we have finite term over infinite hence the limit tend to 0 \[ \lim _{x\to \infty} \frac{\cos x}{ \infty}=0\]
Umm, I don't think that came out the way you wanted it to... All I see are commands.
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I tried to reload, no good. :(
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No, I just tried to read the commands. Taking a course in computer science helps. I just don't bother to memorize the commands for this site.
We can write this as lim (x-> infinity) e^-2x (cos x) so lim (x-> infinity) (cos x)/e^(2x) as x--> infinity e^2x---> infinity we know that cos x lies between -1 and 1 so we have a finite no. divide by infinite , hence the limit tends to zero lim x-> inifinity (finite)/ (infinite)=0
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