Question

Find an equation of the tangent line to the curve x*e^y + y*e^x = 1

Answer 1

At the point (0,1). Forgot about that part of the question.

Answer 2

what i wrote was wrong, it should be
\[e^y+xe^yy'+y'e^x+ye^x=0\]

Answer 3

replace x by 0, y by 1 and solve for y'

Answer 4

Just so you know, my script stopped for some reason and I have no idea what that means so I can't view anything from the equation editor or drawings. I just get "Error".

Answer 5

\[e+y'+1=0\]
\[y'=-e-1\] if my algebra is correct

Answer 6

I've tried reload but nothing.

Answer 7

refresh doesn't work?

Answer 8

"Math Processing Error" Nope, it won't work.

Answer 9

Shouldn't I solve for y' first, then substitute?

Answer 10

I know I need to use the product rule, but how do I solve for y if y is a part of e^y (an exponential)

Answer 11

the derivative of e^y with resepect to x is e^y y' by the chain rule

Answer 12

Just out of curiosity, how did you get that into a pdf?