Question

Find the perimeter of a triangle with vertices (2,4), (-1,3) and (2,-3).

Answer 1

http://openstudy.com/users/myininaya#/updates/4f49a915e4b00c3c5d332011

Answer 2

This question has also been repeated. If you have questions about any of the work let me know.

Answer 3

how did you get 3 radical 5 for one of the sides?
i got 3 radical 10

Answer 4

I used the distance formula for (1,-3) and (2,-3)

Answer 5

the points are (-1,3) and (2,-3).

Answer 6

sorry yah i meant (-1,3)
it is hard looking back and forth

Answer 7

\[\sqrt{(-1-2)^2+(3-(-3))^2}=\sqrt{(-3)^2+(6)^2}=\sqrt{9+36}=\sqrt{45} =\sqrt{9} \sqrt{5}\]

Answer 8

\[=3 \sqrt{5}\]

Answer 9

oh i did (3-(-3)=9, my bad. thank you.