Question

i need to generate the formula to take the derivative of 3 functions and this what i did; f(x)*g(x)*h(x) = f'(x)[g(x)*h(x)]+g'(x)[f(x)*h(x)]+h'(x)[f(x)*g(x)]

Answer 1

Looks good if the LHS is rather d(f(x)*g(x)*h(x))/dx

Answer 2

why would you divide by the dx?

Answer 3

It's just a cautious practice, suppose you have the chain rule!
Here you don't need that caution :)

Answer 4

okay thank you

Answer 5

sorry to bother you guys again, but how would i create a formula for an infinite number of functions

Answer 6

Similar way, derivitive of one times all the others plus derivitive of next times the others etc. This only works for arbitrarily large number of functions, though. Having an infinite number of functions is...rather weird.

Answer 7

i need to come up with a actual formula using N fir differentiated function

Answer 8

I presume you have N functions?

Answer 9

im sorry i still dont follow you

Answer 10

What does N represent?

Answer 11

differentiable functions

Answer 12

??? Try this dN/dx=f_1'(x)f_2(x)...f_n(x)+f_1(x)f_2'(x)...f_n(x)+...+f_1(x)f_2(x)...f_n'(x). Don't quite understand the question anymore

Answer 13

i need to come up with a formula to find the derivative of the product of infinite functions so f(x)*g(x)*h(x)...

Answer 14

It is f'(x)g(x)h(x)...+f(x)g'(x)h(x)...+f(x)g(x)h'(x)... ... where the derived function moves along one each term

Answer 15

so N=the number of equations it would be N'*N+N*N'? would that work?