2. 5 grams of aqueous calcium bromide are mixed with 5 grams of aqueous ammonium carbonate. a.Write a balanced equation, then an ionic equation. b.What precipitate is formed? c.How much precipitate is formed? d.Which reactant has some left over and how many grams are left over?
CaBr2 + (NH4)2CO3------> ? now try to balance it
ok let me try!
im stuck with the parenthesis.....
You'll get CaCO3 and Br(NH4)2
Do you know how to represent the ionic reaction?
ok, so then the answe overall will be A...to balance the equation then right an ionic equation
and no i dont know how
But this is not an option questions, you have to solve everything...
If you want me to help you, click the link http://www.scriblink.com/index.jsp?act=phome&roomid=499&KEY=BA33BDF38B7499DEA17F9252A2767C63
ok
where do i go once i click on the link
It supposed to show a whiteboard... and i'm solving the problem there u.u
I guess I'll just do it here... CaBr2 + (NH4)2 CO3 --> (These are soluble compound so can be separated in iones) (Ca +2) +( Br-) + (NH4 +) + (CO3 -2)---> (This reaction will lead into:) CaBr2 + 2(NH4)2 CO3 --> CaCO3 + 2Br(NH4)2 (Ca +2) + 2( Br-) + 2(NH4 +) + (CO3 -2)---> CaCO3 + 2(Br-) +2(NH4) The calcium carbonate is the precipitate
ok.. you actually broke that down really good. I understand it. Thank you :D
Your welcome... ;)
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