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Chemistry 20 Online
OpenStudy (anonymous):

2. 5 grams of aqueous calcium bromide are mixed with 5 grams of aqueous ammonium carbonate. a.Write a balanced equation, then an ionic equation. b.What precipitate is formed? c.How much precipitate is formed? d.Which reactant has some left over and how many grams are left over?

OpenStudy (anonymous):

CaBr2 + (NH4)2CO3------> ? now try to balance it

OpenStudy (anonymous):

ok let me try!

OpenStudy (anonymous):

im stuck with the parenthesis.....

OpenStudy (anonymous):

You'll get CaCO3 and Br(NH4)2

OpenStudy (anonymous):

Do you know how to represent the ionic reaction?

OpenStudy (anonymous):

ok, so then the answe overall will be A...to balance the equation then right an ionic equation

OpenStudy (anonymous):

and no i dont know how

OpenStudy (anonymous):

But this is not an option questions, you have to solve everything...

OpenStudy (anonymous):

If you want me to help you, click the link http://www.scriblink.com/index.jsp?act=phome&roomid=499&KEY=BA33BDF38B7499DEA17F9252A2767C63

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

where do i go once i click on the link

OpenStudy (anonymous):

It supposed to show a whiteboard... and i'm solving the problem there u.u

OpenStudy (anonymous):

I guess I'll just do it here... CaBr2 + (NH4)2 CO3 --> (These are soluble compound so can be separated in iones) (Ca +2) +( Br-) + (NH4 +) + (CO3 -2)---> (This reaction will lead into:) CaBr2 + 2(NH4)2 CO3 --> CaCO3 + 2Br(NH4)2 (Ca +2) + 2( Br-) + 2(NH4 +) + (CO3 -2)---> CaCO3 + 2(Br-) +2(NH4) The calcium carbonate is the precipitate

OpenStudy (anonymous):

ok.. you actually broke that down really good. I understand it. Thank you :D

OpenStudy (anonymous):

Your welcome... ;)

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