Question

how to make triangular patterns by using nested loops in Java?

Answer 1

Do you want something like this?
*
****
*******

Answer 2

int Column = 5;
int index = 0;
int NumStars = 0;
int NumSpaces = Column/2;

while( NumSpaces >= 0 )
{
NumStars = 2*index + 1;

for( int i = 0; i < NumSpaces; i ++)
System.print(" ");

for( int i = 0; i < NumStars; i ++)
System.print("*");

System.println();
index = index + 1;
NumSpaces = NumSpaces - 1;
}

Answer 3

Thank You .I appreciate your help.
But I wanted more of a number triangle
I tried many times but couldn't figure it out. The output are as follows:
run:
Pattern I
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6
Pattern II
1 2 3 4 5 6
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1
Pattern III
1 2 3 4 5 6
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1
Pattern IV
1
2 1 2
3 2 1 2 3
4 3 2 1 2 3 4
5 4 3 2 1 2 3 4 5
6 5 4 3 2 1 2 3 4 5 6
BUILD SUCCESSFUL (total time: 0 seconds

Answer 4

To get a perfect triangle the width(which i call the column must be an odd number).
Give me some time and i will come up with what you really want

Answer 5

//MaxNumber is the largest possible number to be printed
//Small to Big
void Pattern1( int MaxNumber)
{
for( int i = 1; i <= MaxNumber; i++ )
{
for( int j = 1; j <= i; j++ )
{
System.print(j);
}

System.println();
}
}


//MaxNumber is the largest possible number to be printed
//Big to Small
void Pattern2( int MaxNumber)
{
for( int i = MaxNumber; i > 0 ; i-- )
{
for( int j = 1; j <= i; j++ )
{
System.print(j);
}

System.println();
}
}

char charToNum(char num)
{
switch(num)
{
case 0 : return '0';
case 1 : return '1';
case 2 : return '2';
case 3 : return '3';
case 4 : return '4';
case 5 : return '5';
case 6 : return '6';
case 7 : return '7';
case 8 : return '8';
case 9 : return '9';
default : return '\0';
}
}

String getNum(int num)
{
if( num < 1 )
return "";

if( num == 1 )
return "1";

return charToNum(num) + getNum(num-1) + charToNum(num);
}

//MaxNumber is the largest possible number to be printed
//Small to Big
void Pattern4( int MaxNumber)
{
int spaces = 0;

for( int i = 1; i <= MaxNumber; i++ )
{
spaces = MaxNumber - i;
for( int j = 0; j < spaces; j++ )
{
System.out.print(" ");
}
System.out.println( getNum( i ) );
spaces = spaces + 1;
}
}

Answer 6

For the paterrn 3, the only way to get a really good triangle is to restrict the number s to odd.

Answer 7

Great, it was such a good feeling to get even one of those pattern right. As i was trying this throughout the day.