Question

Find the anti derivative of e^(-x^2)

Answer 1

There isn't one "per se".

Answer 2

How familiar are you with integration/differentiation? :P

Answer 3

Well, i have learned differentiation already and so far i can find the indefinite integral and area under a curve. If that answers your question.

Answer 4

If you are trying to show convergence or divergence for some interval, that can be done
this integral cannot
http://www.wolframalpha.com/input/?i=e%5E(-x%5E2)dx&t=crmtb01

Answer 5

if it were perhaps xe^(-x^2)
that would be very different

Answer 6

Do you know about parametric differentiation under the integral sign turing?

Answer 7

Leibniz rule stuff?
a little bit only...

Answer 8

i actually did go on that site before i went here. My main point in asking this question is because i have the find the area under two curves and y=e^(-x^2) is one of the equations. (The other one is y=x^3 -x +1)

Answer 9

Well anyway, thank you Malevolence and TuringTest

Answer 10

I think I have seen this kind of problem before.
I have to think about that one though, pretty tricky
I'll get back to you

Answer 11

If you can that would be wonderful :) Would you like me to post it as a separate question instead?

Answer 12

I was going to say, instead of
\[\int\limits e^{-x^2}dx\]
consider:
\[\int\limits_{-\infty}^{\infty}e^{-\rho x^2}dx=\sqrt{\frac{\pi}{\rho}}, \rho >0.
\]
From this you can derive relations for:
\[\int\limits_{-\infty}^{\infty}x^{2k}e^{- \rho x^2}dx \] for positive integers k. The odd powered ones go to zero (odd function over symmetric bounds).