Question

15x to the third -20x squared -7x+23 over 3x-1? Dividing polynomials

Answer 1

15x^3-20x^2-7x+23)/(3x-1)


Divisor
|
| 5x^2-5x-4 < ------ Equation
v ______________________
(3x-1) | 15x^3-20x^2-7x+23)
15x^3-5x^2 -multiply bottom row (-1)
----------- -Add- "Taking Difference"
0x^3-15x^2
-15x^2+5x -multiply bottom row (-1)
---------- -Add- "Taking Difference"
0x^2-12x+23
-12x+4 -multiply bottom row (-1)
-------- -Add- "Taking Difference"
0x+19 <---Remainder


5x^2-5x-4 + 19/(3x-1) = Equation + Remaind/Divisor

Answer 2

Is it still over 3x-1? isnt 19 the remainder

Answer 3

yes the remainder goes over the divisor. I don't know how to make fraction symbols on here. It will be that new equation on top plus the remainder divided by the original divisor.

Answer 4

Thank you sir!

Answer 5

This picture might help explain the process a little better.