Write complete ionic equation to show the reaction of aqueous lead(II) nitrate with aqueous potassium sulfate to form solid lead(II) sulfate and aqueous potassium nitrate.

Question

rogue · Answer

$$Pb (NO_3)_2 (aq) +  K_2 SO_4 (aq) \rightarrow PbSO_4 (s) + 2KNO_3 (aq)$$Everything except the lead sulfate is soluble, so they all dissociate.$$Pb^{2+} +  2NO_3^-  +  2K^+ + SO_4^{2-} \rightarrow PbSO_4 (s) + 2K^+ + 2NO_3^-$$Cancel out stuff that appears on both sides, and your net ionic equation is$$Pb^{2+} (aq) + SO _{4}^{2-} (aq) \rightarrow PbSO_4 (s)$$