Question

integrate 2t +(2/t) from 1 to e

Answer 1

\[\int\limits_{1}^{e} 2t + 2/t dt = [t^2 + 2\ln(t)] \]

so

\[f(t) = t^2 + 2\ln(t)\]

evaluate by finding f(e) - f(1)

Answer 2

could you show me... please

Answer 3

well f(e) = e^2 + 2 x ln(e)
\[f(e) = e^2 + 2 \times 1\]

\[f(x) = e^2 + 2\]

f(1) = 1^2 + 2ln(1)

f(1) = 1

then f(e) - f(1) = e^2 + 2 - 1

the value of the definite integral is e^2 + 1

Answer 4

arigato!