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Chemistry 19 Online
OpenStudy (anonymous):

Considering ammonia production with 53% yield, what mass of nitrogen and what mass of hydrogen would be needed to produce the actual yield of 100.0 moles of ammonia? I know I need 190 moles of NH3 to produce 100 moles of NH3 The formula I'm using right now is 3H2+N2=2NH3

OpenStudy (jfraser):

the 190 moles you found it the theoretical yield. Use the balanced reaction to convert that to moles of nitrogen and moles of hydrogen \[190mol NH{_3} * (\frac{1mol N{_2}}{2mol NH{_3}})\] and \[190mol NH{_3} * (\frac{3mol H{_2}}{2mol NH{_3}})\] This gets you the moles of raw materials that should get you 190 moles of ammonia, but will only get you 100moles due to the 53% yield.

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