Question

HELP!!!!!!!
SOLVE: 4^x - 2= 8^6

Answer 1

is this your question?
\[4^{x-2}=8^6\]

Answer 2

looks like 2 is not part of the power.....

Answer 3

I assume it's that
we have \(8^6\), it can be written as
\[(8^2)^3= 64^3\]
we know that \(4^3=64\)
so
\[(8^2)^3= 64^3=(4^3)^3\]
this is equal to \(4^9\)
so
we have
\[4^{x-2}=4^9\]
equating the powers we get
\[x-2=9\]
add 2 to both sides, we get
\[x=11\]

Answer 4

Or, You can simply take it in the base of two.
\[4^{x-2} = 8^{6}\]
\[(2^{2})^{x-2} = (2^{3})^{6}\]
Therefore we have,
2x - 4 = 18
=> x = 11.
Basically the aim is to get a same base.
Irrespective of how you do it. :)

Answer 5

AAHH YOU GUYS THANK YOU SOOO MUCH :3