Find the cross product of j x k (And yes, that is all that is given, so I have no idea what I'm doing)

Question

lukecrayonz · Answer

Here is the full picture, number two. http://screensnapr.com/e/kvvXYJ.png

anonymous · Answer

ixj = k 
jxk = i 
kxi = j

agreene · Answer

j x k = jk sin (theta) i

agreene · Answer

well, these are unit vectors so what lady in red said is true.

anonymous · Answer

read this http://omega.albany.edu:8008/calc3/cross-product-dir/cornell-lecture.html

lukecrayonz · Answer

so jxk = i?

lukecrayonz · Answer

I feel like I need more than that for my answer.

agreene · Answer

you can do the work with the definition of cross products, but you'll find the answer to be i hat (the i unit vector)

lukecrayonz · Answer

And sketching it?

agreene · Answer

assuming it's a normal plane (right hand rule) it will be a line on the "x" axis one unit long

phi · Answer

$$\left| \begin{matrix}i &j& k \ 0& 1&0 \0&0&1\end{matrix} \right|=i\cdot1-j\cdot 0+k\cdot 0=i$$

lukecrayonz · Answer

Is it possible to sketch it here? I don't get what you mean by the right hand rule, and I looked at that page she gave me but it still doesn't make any sense.

agreene · Answer

http://en.wikipedia.org/wiki/File:Right_hand_rule_cross_product.svg

agreene · Answer

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