What is the formula for compound interest with monthly investments?
C=P(1+r)^n
It is P(1+i/12)^(12n), where P is principal, i is nominal annual interest, n is number of years.
For example, $25000 with 2.5% nominal annual interest would yield $25000(1+0.00208333)^120 after 10 years.
Now that is interest compounded monthly, not "with monthly investments." Looking at your other post, I see you really did mean "with monthly investments," and you need quarterly interest. So the latter would be P(1+i/4)^(4n) Example: $25000(1+0.00625)^40 for $25000 at 2.5% nominal APR for 10 years.
To incorporate the investments is a little trickier. Instead of P(1+i/4)^(4n) you have P(1+i/4)^(4n) + m(1-(i/12)^(12n+1))/(1-(i/12)). So, if you would like, I'll go back to your other post and see if I can turn this into a solution for you.
(m is the monthly deposit amount, BTW)
That will be very helpful, because I am so lost!
First a typo correction: P(1+i/4)^(4n) + m(1-(1+i/12)^(12n+1))/(1-(1+i/12)). Second, I will go to your other question and show you the process there now.
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