Let R be the region in the xy plane between the graphs of y=e^x and y=e^-x from x=0 to x=2. a. Find the volume of the solid generated when R is revolved about the x axis.
lol.... your teacher really needs a new problem to hand out ....
if you still have questions from that, feel free to ask
regina were never gunna get help
read the material that has already been presented a thousand times on this same quesiton and if you still have questions; then be specific please
what is a washer and shell?
a washer represents that shape of the area that this thing resemebles; |dw:1330382298488:dw| when its spun about the axis
a shell is the type of object you get when you spin it in another fashion; it creates a "can" or "cylindar"
|dw:1330382370334:dw| the shell
each method of spinning has its pros and cons
|dw:1330382453377:dw| the washer method is prolly easiest on this for alot of people you take the area of a circle generated by the spin: pi R^2 and subtract out the part you dont want: -pi r^2 since our upper and lower functions are what determines our radiuses ... \[\int pi [f(x)]^2dx-\int pi [g(x)]^2dx\] or \[pi \int [f(x)]^2- [g(x)]^2dx\] are your basic interpretation for your volumes of revolution
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