Question

I need assistance with Factoring a Quadratic equation.

Answer 1

\[2x^2-11x+5=0\]

Answer 2

do you know to find the solutions to this equation?

Answer 3

(2x-1)(x-5)

Answer 4

I knew how to find the solution but I was unsure about the concept of finding the factoring portion.

Answer 5

(2x-1)(x-5)=0 now solve 2x-1=0 and x-5=0

Answer 6

well when you're equation is in the form ax^2+bx+c? OK? tell me what is a in your equation?

Answer 7

It's \[2x^2-11+5\]

Answer 8

Oh sorry, I read that wrong, 2x^2 is My A

Answer 9

a is 2. Understand? now tell me what are the solutions of your equation?

Answer 10

I understand the parts of a quadratic equation but I was unsure about factoring the actual equation. After the factoring, it's a breeze to find out the rest of the answer.

Do you think you can break down the process of how (2x-1)(x+5) was attained?

Answer 11

I'm trying to explain that to you...when you have the solutions of the quadratic equation and you know what is your ''a'', then you can write it as a(x-x1)(x-x2) where x1 and x2 are your solutions

Answer 12

in this case your solutions are x1=1/2 and x2=5 and a=2 so you can write your equation like this: 2(x-1/2)(x-5) , you can leave it like this, or if you want you can multiply first two terms and you get (2x-1)(x-5)