Question

is each function odd, even or neither?

f(x)=1-x^2/2+x^2

Answer 1

A function is odd if
f(-x) = - f(x)

And it is even if
f(-x) = f(x)

So to find out whether your function is odd or even, evaluate
f(-x)
and see if it is equal to either f(x) or -f(x).

What do you find?

Answer 2

you might want to simply first
\[f(x)=1-{x^2\over2}\]

Answer 3

I think the function is
\[ f(x) = \frac{1-x^2}{2 + x^2} \]
but Danyel should clarify.

Answer 4

i diden't even think of that

Answer 5

this is what I came up with yes