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Use the intermediate value theorem to show that f(x) has a zero in the given interval. Please show all of your work. f(x)=2x^5-7x^3-4x^2+3; [0.6, 0.7]
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replace x by 0.6 and by 0.7 one value will be postive, the other negative conclude that since this function is continuous it must take on every value in between the postive and negative one, and so is zero somewhere
Is this the answer?
it is once you evaluate the function at 0.6 and at 0.7
Well I need the answer because this work is due tonight & I don't know how to do it.
replace x by 0.6 and use a calculator repeat with 0.7
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