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Proof: There is a unique real number b such that f(x) = 2x^2 - 3x + 4 has a derivative of 0 at x=b.
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Alright, proof by assume. f'(x)=4x-3=0, 4x=3, x=3/4=b, which satisfies ∃b,(b∈ℝ)|f'(b)=0
In fact, ∃!b,(b∈ℝ)|f'(b)=0 is true because we can determine that there is only one solution such that 4x-3, since this is a first degree polynomial.
wow. that makes total sense. just have to look at it the right way. you like proofs, right? want to help more?
Sure.
Please post it as a separate question, though; don't like scrolling down.
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