Question

how would i find the domain and vertical asymptotes for f(x)=x-1/x^2-2x+1?

Answer 1

set the denominator = 0 and solve , then eliminate the x's from the reals

Answer 2

The domain is all real number except \[x \neq1\]

and the vertical asymptote of the function is at x=1 itself.

Answer 3

so the vertical is the top while the domain is x-1=x^2-2x+1 and then solve?

Answer 4

no no

Answer 5

pls explain

Answer 6

you should factorize the denominator as the denominator will influence your domain and vertical asymptote.. what mathg8 try saying is that you should put
x^2-2x+1 = 0

Answer 7

oh, then what role does x-1 play?

Answer 8

vertical i assume?

Answer 9

You actually need that if you want to find the horizontal asymptote of your function.. but as for your question right there, the (x-1) is kinda useless...

Answer 10

there are horizontal and slant asymptotes that depend on the numerator

Answer 11

oh, don't need those then... but what does x^2-2x+1 tell me then...

Answer 12

here's an easy example : what is the domain of 1/x ?

Answer 13

all real numbers?

Answer 14

well ... no ...what happens if you divide by 0?

Answer 15

besides 0

Answer 16

yes ! you can't divide by ZERO , that's why we exclude the values of x for which the denominator becomes ZERO

Answer 17

making the denominator =0 we find the values of x that make the denominator zero ...so we have to eliminate them from the domain

Answer 18

got it got it

Answer 19

ty

Answer 20

thanks for meds...

Answer 21

my pleasure