y varies inversely as twice x. when x=9, y=2. find y when x=3

Question

y varies inversely as twice x. when x=9, y=2.  find y when x=3

anonymous · Answer

$$(y) \alpha \frac{1}{2x}$$
Thus,
$$y=k \frac{1}{2x}$$ where k is an arbitrary constant. 

When x=9, y=2

2=k/(2*9)
k=36

When x=3,

y= (36) /(2*3)
y=6

amistre64 · Answer

its polite to at least give people a thank you for their help.  medals are meant as a means to give thanks as well; but not a dire requirement :)

anonymous · Answer

i was comparing what I had with what you had to make sure I understood the problem and how the answer was derived.  Thank you for your help!!!

anonymous · Answer

what is the solution set for Ix-6I+3<10

anonymous · Answer

|x-6| +3 <10
|x-6| < 7 

Breaking the abs sign,

x-6 <7 or 
x-6>-7

anonymous · Answer

thanks

anonymous · Answer

Np!