Question

y varies inversely as twice x. when x=9, y=2. find y when x=3

Answer 1

\[(y) \alpha \frac{1}{2x}\]
Thus,
\[y=k \frac{1}{2x}\] where k is an arbitrary constant.

When x=9, y=2

2=k/(2*9)
k=36

When x=3,

y= (36) /(2*3)
y=6

Answer 2

its polite to at least give people a thank you for their help. medals are meant as a means to give thanks as well; but not a dire requirement :)

Answer 3

i was comparing what I had with what you had to make sure I understood the problem and how the answer was derived. Thank you for your help!!!

Answer 4

what is the solution set for Ix-6I+3<10

Answer 5

|x-6| +3 <10
|x-6| < 7

Breaking the abs sign,

x-6 <7 or
x-6>-7

Answer 6

thanks

Answer 7

Np!