Question

Does anyone know all to do quadratic equations?

Answer 1

yup

Answer 2

I might be able to help, if not .Sam. definitely will.

What's your question?

Answer 3

I know. Bring on your question!

Answer 4

cut to the chase

Answer 5

I have a 3 problems that i don't know how to apply to the formula.

Answer 6

Post them...? Lol.

Answer 7

x^2 /3 +2x= -2

Answer 8

next problem: x^2 + 5x = 3

Answer 9

\[\frac{x ^{2}}{3+2x}=-2\]
Is it?

Answer 10

almost. only the (3) is in the denominator

Answer 11

\[x ^{2}=-2(3+2x)\]
\[x ^{2}=-6-4x\]\[x ^{2}+4x+6=0\]

Answer 12

okay cool then I would just plug in a, b, c

Answer 13

a=1 b=4 c=6
\[x=\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]

Answer 14

great and thanks!

Answer 15

welcome

Answer 16

x^2 + 5x = 3 next problem

Answer 17

I would just move these over and set to zero and plug in formula

Answer 18

\[x^2 + 5x = 3 \]
\[x^2 + 5x -3=0\]
a=1 b=5 c=-3

Answer 19

thanks. last problem. I posted this one before. but noone on here seemed get it correct. maybe you can help.

Answer 20

\[\sqrt{-3} \times \sqrt{-128}\] this is using imaginary numbers (i)