Question

Find the derivative of the function.

y=(3 x^2 - 6 x + 1)^5

Answer 1

We have
\[ y=(3 x^2 - 6 x + 1)^5 \]
\[\frac{dy}{dx}= 5\times (3x^2-6x+1)^4 \times \frac{d}{dx}(3x^2-6x+1)\]
we get
\[\frac{dy}{dx}= 5\times (3x^2-6x+1)^4 \times (6x-6)\]

Answer 2

use the chain rule dy/dx = dy/du x du/dx

dy/dx = 5(3x^2 - 6x +1)^4 x (6x - 6)

Answer 3

ok is 5x? or 5 times (x)?

Answer 4

5 times

Answer 5

thanx