Question

someone please help....

Find the value of x: 2^1/x +1= 3.3846

Answer 1

2^(1/x)+1=3.3846
2^(1/x)=2.3846
ln(2^(1/x))=ln(2.3846)
ln(2)/x=ln(2.3846)
x=ln(2)/ln(2.3846)

Answer 2

\[\approx .798\]

Answer 3

i dont understand how u got to this part:
ln(2)/x=ln(2.3846)
then..x=ln(2)/ln(2.3846)

Answer 4

2^(1/x)+1=3.3846
2^(1/x)=2.3846
ln(2^(1/x))=ln(2.3846) multiple both side by ln
ln(2)/x=ln(2.3846) property of logarithms, the exponent goes to
the front -> 1/x ln(2) rewrite -> ln(2)/x

x=ln(2)/ln(2.3846) solving for x

Answer 5

thanks