Question

Integral of tan^2(x)sec(x)

Answer 1

u is Sec(x)!!!!

Answer 2

du is tan^2(x) dx.. the rest is for myin.

Answer 3

not quite bahrom

Answer 4

\[\int\limits_{}^{}\tan(x) \cdot \tan(x) \sec(x) dx=\tan(x) \cdot \sec(x)-\int\limits_{}^{}\sec^2(x) \cdot \sec(x) dx\]

Answer 5

oh wait lol i got it the other way around hahaha

Answer 6

And you can look at the integral sec^3(x) and use integration by parts there

Answer 7

oh wait i didn't need to do what i did

Answer 8

\[\int\limits_{}^{}(\sec^2(x)-1)\sec(x) dx=\int\limits_{}^{}\sec^3(x) dx-\int\limits_{}^{}\sec(x) dx\]

Answer 9

that person is leaving, just so you know
they told me on another post

Answer 10

\[\int\limits_{}^{}\sec^3(x) dx=\int\limits_{}^{}\sec^2(x) \sec(x)dx=\tan(x) \sec(x)-\int\limits_{}^{}\tan(x) \sec(x) \tan(x) dx\]
\[\tan(x) \sec(x)-\int\limits_{}^{}(\sec^2(x)-1) \sec(x) dx\]

Answer 11

:(

Answer 12

I was doing problems with them for quite a while, but don't worry
pretty sure they got what you were saying

Answer 13

yay i think there is enough info here

Answer 14

thanks to all of you! I got it now.