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Prove that the triangle with vertices D(-,3), E(1,6), and F(2,4) is an isosceles right triangle.
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What the coordinate for D?
(0,3)
use the distance formula to find the length of EF and DF.
I just need to prove how to do it.
okay.. well once you find out that both sides are equal...
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you find the length of the third side.
then plug the values into pythagorean theorem
DE should be the hypotenuse.
if the values make sense, and both sides equal each other, then the triangle has to be a right triangle.
And since only two sides are congruent, is must be isoceles.
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So, thus you can prove it's an isosceles right triangle.
\[distance=\sqrt{(x _{1}-x _{2})^2+(y _{1}-y _{2})^2}\]
\[a^2+b^2=c^2\] ^pythagorean theorem
:) hope that helps
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