Question

Solve the following system of equations.

2x – 3y + z = –1
3x + 2y + 2z = –1
x – y – 3z = –4

Answer 1

What method you want to use ?

Answer 2

Solve the last equation for x. Then use it to eliminate x from the first two. This results in two equations iin y and z you can solve

Answer 3

i just don't know how to do this...it confuses me, i keep getting the wrong answer. Allamiro, elimination would probably be the best!

Answer 4

Use matrices, yo. They're so much simpler. But if you're really against it... To eliminate, let's look for similar terms.

2x–3y+z=–1
3x+2y+2z =–1
x–y–3z=–4

Oh wait, it'd be awful nice if

2(x–y–3z)=2(–4)
could be added on to
2x–3y+z=–1

Do you follow?

Answer 5

from the last equation: x=-4+y+3z
Plug this in for x in the two first.
Let me know what you get.

Answer 6

You take the first equation

2x – 3y + z = –1

and the third
x – y – 3z = –4


multiply 1 * 3 and add it to equation 3

7x-10y = -7


take equation 1 and 2

2x–3y+z=–1
3x+2y+2z =–1


multiply 1 * 2 and subtract it

x -8y = 0

you take the results

Answer 7

you will have
7x-10y = -7

x -8y = 0

Answer 8

I m not sure about the numbers you may want to check my subtraction and addition but you should get the point following the same method find X and Y

Answer 9

We mult by 7 the second one and subtract
-10Y + 8*7 Y =-7

Answer 10

Thanks for your help guys, i still haven't came up with an answer, so i think ill just skip it.. i was hoping you could solve it for me so i could use it for future reference

Answer 11

After all this man you need just to use the calculator wooow

Answer 12

Ill look it over again, thanks for your help & hard work