Question

Write an equation in-slope intercept form for the line that passes through (-3,2) and is perpendicular to the line described by y=3/4x + 4

Answer 1

what do you think

Answer 2

That I would use the reciprical -2/3 for the slope

Answer 3

What aboutthe y-intercept of a perpendicular line?

Answer 4

2?

Answer 5

your reciprocal would not be -2/3 it would be -4/3

Answer 6

yeah use the reciprocal of the slope

Answer 7

-4/3

Answer 8

Once you have determined your slope,
use:
(y-y1) = m (x-x1) as
(x1,y1) is equal to (-3,2)

Answer 9

y-y1=m(x-x1)

Answer 10

Yeah, typo.

Answer 11

y=-4/3x-2?

Answer 12

y - 2 = -4/3(x +3)
y - 2 = -4x/3 - 4

y = -4x/3 - 2

yep :D

Answer 13

So I need to write it in slope-intercept. What is that formula used?

Answer 14

y = mx + b is slope intercept.

m -> slope
b -> y-intercept

your equation is...
y=-4/3x-2
-4/3 = m -> slope
-2 = b -> y-intercept

y = mx + b gives you the slope and y-intercept of a line, enabling easy graph.

y-y1 = m(x-x1) is point-slope form, as it gives a point and the slope
x+y + c = 0, where c = some number like 1,2,3,4, 14/6, etc. is the general equation for a line.