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Use standard trig identities to show that cos(x+(pi/2))=-sin(x). For each step indicate which identity you used.
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cos(x+(pi/2))=cos(x)cos(pi/2)(+-)sin(x)sin(pi/2) cos(pi/2)=0 sin(pi/2)=1
more commonly just the - in between.
using the sum of angles theorem \[\cos(x + \pi/2) = \cos(x)\times \cos(\pi/2) - \sin(x) \times \sin(\pi/2)\] cos(pi/2) = 0 and sin(pi/2) = 1 = 0 - sin(x) x 1 = -sin(x)
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