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Mathematics 13 Online
OpenStudy (anonymous):

get the value from..

OpenStudy (anonymous):

\[\lim_{x \rightarrow \infty} (\cosh^1 x - \ln x)\]

sam (.sam.):

the cosh power 1 or -1?

OpenStudy (anonymous):

-1

OpenStudy (anonymous):

-infinity?

OpenStudy (anonymous):

-∞

OpenStudy (anonymous):

ln∞ -> ∞ cosh(∞) -> ∞ but 1/∞ -> 0 so 0-∞

sam (.sam.):

\[\huge \lim_{x \rightarrow \infty}(cosh ^{-1}x-lnx)\] \[\huge \cosh ^{-1}\infty-lnx\]

OpenStudy (anonymous):

Was i right?

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