Question

solve the equation. radical 3x-5=4

is the correct answer 3
my options are
A.7
B.3
C.1/3
D.49

Answer 1

sqrt(3x - 5) = 4


3x - 5 = 4^2


3x - 5 = 16


3x - 5+5 = 16+5


3x = 21


3x/3 = 21/3


x = 7


So the answer is choice A

Answer 2

thank you

Answer 3

you're welcome

Answer 4

what about when i have a equation like this: radical 6m-5=m

Answer 5

sqrt(6m - 5) = m


6m - 5 = m^2


0 = m^2 - 6m + 5


m^2 - 6m + 5 = 0


Now use the quadratic formula to solve for m


m = (-b+-sqrt(b^2-4ac))/(2a)


m = (-(-6)+-sqrt((-6)^2-4(1)(5)))/(2(1))


m = (6+-sqrt(36-(20)))/(2)


m = (6+-sqrt(16))/2


m = (6+sqrt(16))/2 or m = (6-sqrt(16))/2


m = (6+4)/2 or m = (6-4)/2


m = 10/2 or m = 2/2


m = 5 or m = 1


So the possible solutions are m = 5 or m = 1


You would need to check if they are really indeed solutions. I'll let you do this.

Answer 6

my options are A. 1
B.5
C. 1,5
or D no real solution

Answer 7

choice C, when you do check the solutions, you'll find that both 1 and 5 are solutions

Answer 8

ok thank you

Answer 9

np