Question

WILL GIVE MEDALS
A diverging lens of focal length -8cm projects the image of an object onto a wall. What is the object distance if the image is virtual, upright, and 90% of the object size?

Answer 1

1/di + 1/do = 1/f,
where di is the distance from the lens to the image, do is the distance from the object to the lens, and f is the focal distance of the lens.
Note that for the diverging mirror f should be negative. This ensures that di is negative and that the image is on the left of the lens (a virtual image), this is the only possibility for a diverging lens.

Answer 2

what answer didyou get?

Answer 3

I didn't do it yet ... what did you get?

Answer 4

di=.9do

Answer 5

16.89?

Answer 6

isnt it -8/1.9=do?

Answer 7

ok ya i got that :) THANKS A LOT MAN