When 2.1 L of propane gas is completely combusted to form water vapor and carbon dioxide at 350°C and 0.917 atm, what mass of water vapor results?

Question

anonymous · Answer

do you have the equation?

anonymous · Answer

nope, i have no idea :(

anonymous · Answer

C3H8 + 5O2 ---> 3CO2 + 4H2O this is you equation..

anonymous · Answer

okay but how do i solve it..

anonymous · Answer

use PV=nRT and find the no. of mol of propene

remember to convert the temp. into kelvin as such (350+273.15)=623.15K
u've got the P = 0.917 atm and volume = 2.1L and R = 0.08206 (atm*L)(mol*K)

anonymous · Answer

after that you can see that 1 mol of propene is the same as 5 mol of water vapor. so the ratio is 1:5