Mathematics
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OpenStudy (anonymous):
Find the y-coordinate of the vertex for the following function:
g(x) = x2 - 3x + 2
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OpenStudy (anonymous):
Let's complete the square
OpenStudy (anonymous):
ok thats what im most confused on to idk how i would even start to do this
:(
OpenStudy (anonymous):
ok you want to add (b/2)^2 and subtract (b/2)^2
OpenStudy (anonymous):
what is b/2? ?
OpenStudy (anonymous):
x^2-3x+(3/2)^2-(3/2)^2+2
(x-3/2)^2-9/4+2
(x-3/2)^2-1/4
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OpenStudy (anonymous):
ax^2+bx+c
To complete the square you take 1/2 of b and square it
OpenStudy (anonymous):
you have to add this (b/2)^2 and also subtract it so its an equivalent expression
OpenStudy (anonymous):
so i would take x-3/2 n times that by x-3/2?
OpenStudy (anonymous):
so b/2 in this case is 3/2
OpenStudy (anonymous):
thats completing the square, you don't do any more after what i wrote
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OpenStudy (anonymous):
if you do, you'll end up back where you started at x^2-3x+2
OpenStudy (anonymous):
so this is the equation of a parabola in the form
y=a(x-h)^2+k
OpenStudy (anonymous):
The vertex is (h,k)
OpenStudy (anonymous):
so the y coordinate is -1/4?
OpenStudy (anonymous):
right
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OpenStudy (anonymous):
and x-coordinate is 3/2
OpenStudy (anonymous):
okay right on thank you for your help brotha!!
OpenStudy (anonymous):
And you know what the y-coordinate is right?
OpenStudy (anonymous):
or sista :P whatever it may be
OpenStudy (anonymous):
you're welcome
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OpenStudy (anonymous):
yes i undertand now!! ur help was great thx again