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Mathematics 13 Online
OpenStudy (anonymous):

Find the y-coordinate of the vertex for the following function: g(x) = x2 - 3x + 2

OpenStudy (anonymous):

Let's complete the square

OpenStudy (anonymous):

ok thats what im most confused on to idk how i would even start to do this :(

OpenStudy (anonymous):

ok you want to add (b/2)^2 and subtract (b/2)^2

OpenStudy (anonymous):

what is b/2? ?

OpenStudy (anonymous):

x^2-3x+(3/2)^2-(3/2)^2+2 (x-3/2)^2-9/4+2 (x-3/2)^2-1/4

OpenStudy (anonymous):

ax^2+bx+c To complete the square you take 1/2 of b and square it

OpenStudy (anonymous):

you have to add this (b/2)^2 and also subtract it so its an equivalent expression

OpenStudy (anonymous):

so i would take x-3/2 n times that by x-3/2?

OpenStudy (anonymous):

so b/2 in this case is 3/2

OpenStudy (anonymous):

thats completing the square, you don't do any more after what i wrote

OpenStudy (anonymous):

if you do, you'll end up back where you started at x^2-3x+2

OpenStudy (anonymous):

so this is the equation of a parabola in the form y=a(x-h)^2+k

OpenStudy (anonymous):

The vertex is (h,k)

OpenStudy (anonymous):

so the y coordinate is -1/4?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

and x-coordinate is 3/2

OpenStudy (anonymous):

okay right on thank you for your help brotha!!

OpenStudy (anonymous):

And you know what the y-coordinate is right?

OpenStudy (anonymous):

or sista :P whatever it may be

OpenStudy (anonymous):

you're welcome

OpenStudy (anonymous):

yes i undertand now!! ur help was great thx again

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