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Verify: sec²cotx-cotx = tanx
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you will need the following identities: sec^2(x) = 1 - tan^2(x) and cot(x) = 1/tan(x). if you make the right substitutions it's practically self working
...but can you show me?
factor out a cotx first from the left side
\[cotx(\sec^2x-1)=tanx\] \[cotx(\tan^2x)=tanx\] \[\frac{1}{tanx}\tan^2x=tanx\] tanx=tanx
Multiply both sides by tan x, simplify to get \[\sec ^{2}x-1=\tan ^{2}x\]which is an identity.
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Nice Dockworker.
u too
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