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Mathematics 18 Online
OpenStudy (anonymous):

Verify: sec²cotx-cotx = tanx

OpenStudy (anonymous):

you will need the following identities: sec^2(x) = 1 - tan^2(x) and cot(x) = 1/tan(x). if you make the right substitutions it's practically self working

OpenStudy (anonymous):

...but can you show me?

OpenStudy (anonymous):

factor out a cotx first from the left side

OpenStudy (anonymous):

\[cotx(\sec^2x-1)=tanx\] \[cotx(\tan^2x)=tanx\] \[\frac{1}{tanx}\tan^2x=tanx\] tanx=tanx

OpenStudy (anonymous):

Multiply both sides by tan x, simplify to get \[\sec ^{2}x-1=\tan ^{2}x\]which is an identity.

OpenStudy (anonymous):

Nice Dockworker.

OpenStudy (anonymous):

u too

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