In the given figure (I hv attached it separately) ABC is a right angled triangle. AngleB=90 degree, AB = 28 cm and BC = 21 cm. With AC as diameter, a semicircle is drawn and with BC as radius a quarter circle is drawn. Find the area of the shaded region correct to two decimal places.

Question

In the given figure (I hv attached it separately) ABC is a right angled triangle. AngleB=90 degree, AB = 28 cm and BC = 21 cm.  With AC as diameter, a semicircle is drawn and with BC as radius a quarter circle is drawn.  Find the area of the shaded region correct to two decimal places.

anonymous · Answer

figure please !!!

anonymous · Answer

@baby, you want complete solution or are u confused by the wrong answer given in R.D. Sharma's book??

correct answer is 428.75

anonymous · Answer

here is the figure and the solution...

anonymous · Answer

first use Pythagoras Theorem to find/calculate AC = 35

shaded area = [(area of triangle ABC = 1/2 x 21 x 28) + (Area of semicircle on AC = 1/2 x 22/7 x 17.5 x 17.5)] - (area of sector/quadrant with radius 21 cm = 1/4 x 22/7 x 21 21)