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hi im new to partial differentiation, and im wondering whether im doing it correctly...
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Find\[\delta z / \delta r\] when (r,theta) =(2, pi/4) if \[z=4e ^{x} \ln y, x=\ln \left( r \cos \theta \right), y=r \sin \theta\]
the basic chain rule is dz/dr = dz/dx (dx/dr) + dz/dy (dy/dr), d=del the answer i'd obtained is \[dz/dr = \left( 4e ^{x}*\ln y \right)\left( 1/r \cos \theta \right)+\left( 4e ^{x} *1/y \right)\left( \sin \theta \right)\]
and im not sure when to substitute the (r, theta)=(2, pi/4) into the expression
I would have to study your answer, but just plugging in for x and y \[ z= 4 r cos\theta ln( r sin \theta ) \] and then take the derivative wrt r, treating theta as a constant
oo k i try again
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oh i got it, tqvm :D
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