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The area of a rectangular pool is given by the trinomial 8y2 + 4y – 12. What are the possible dimensions of the pool? Use factoring.
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8y2+4y-12 = 4(2y2+y-3) = 4(2y2+3y-2y-3)=4(y(2y+3)-(2y+3))=4(y-1)(2y+3)=0 say so either y-1=0 or 2y+3=0 or y=1 or y=-3/2 as dimension cannot be negative.so valid y for rectangle is 1
8y2 + 4y – 12 =2(4y2 + 2y -6) = 2(2y-2)(2y+3) L=4y+6 W=2y-2 OR L= 2y+3 W=4y-4
(–2y – 2) and (–4y – 6) (2y – 2) and (4y + 6) (2y – 2) and (4y + 6) (2y + 2) and (4y – 6)
from the options (2y – 2) and (4y + 6) fits
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