Question

e^4(-2log,x,8)=e^24


, ,=base

Answer 1

e^(4(-2log^x(8)))=e^(24)

e^(-8log^x(8))=e^(24)

ln(e^(-8log^x(8)))=ln(e^(24))

-8log^x(8)ln(e)=ln(e^(24))

-8log^x(8)ln(e)=(24)

log^x(8)=-(3)/(ln(e))

x^(log^x(8))=x^(-(3)/(ln(e)))

8=x^(-(3)/(1))

8=(1)/(x^(3))

(1)/(x^(3))=8

(1)/(8)=x^(3)

x^(3)=(1)/(8)

\[x=\sqrt[3]{1/8}\]