@satellite73 would u be so kinda of to help me realize where I went wrong with this... "solve the differential equation dy/dx- 1/2y cos(x) given that f(0)- 2

Question

@satellite73   would u be so kinda of to help me realize where I went wrong with this... "solve the differential equation dy/dx- 1/2y cos(x) given that f(0)- 2

liizzyliizz · Answer

f(0)=2 * and kind * so sorry for the typo

amistre64 · Answer

there is no equation; just a diffy expression.

liizzyliizz · Answer

I messed up in the beginning I believe when i separated the variables

liizzyliizz · Answer

y is what screwed me up and *gasp* my homework has Lied to me then -_-

liizzyliizz · Answer

dy/dx= *

amistre64 · Answer

im assuming its an homogenous thingy

$$dy/dx- 1/2y cos(x)=0$$
$$dy/dx= 1/2y cos(x)$$
$$dy= 1/2y cos(x)dx$$
$$2ydy= cos(x)dx$$

amistre64 · Answer

something akin to that i beleive

amistre64 · Answer

so

y^2 = sin(x) + C

amistre64 · Answer

when x=0 sin(0) = 0

2^2 = C

amistre64 · Answer

y^2 = sin(x) + 4

liizzyliizz · Answer

|dw:1330655997254:dw| I had a typo.  dy/dx- and dy/dx are two completley different things o.o  because I got y^2= sin(x) + 4 when i did it, but i feel like I did something wrong there.