Question

@satellite73 would u be so kinda of to help me realize where I went wrong with this... "solve the differential equation dy/dx- 1/2y cos(x) given that f(0)- 2

Answer 1

f(0)=2 * and kind * so sorry for the typo

Answer 2

there is no equation; just a diffy expression.

Answer 3

I messed up in the beginning I believe when i separated the variables

Answer 4

y is what screwed me up and *gasp* my homework has Lied to me then -_-

Answer 5

dy/dx= *

Answer 6

im assuming its an homogenous thingy

\[dy/dx- 1/2y cos(x)=0\]
\[dy/dx= 1/2y cos(x)\]
\[dy= 1/2y cos(x)dx\]
\[2ydy= cos(x)dx\]

Answer 7

something akin to that i beleive

Answer 8

so

y^2 = sin(x) + C

Answer 9

when x=0 sin(0) = 0

2^2 = C

Answer 10

y^2 = sin(x) + 4

Answer 11

I had a typo. dy/dx- and dy/dx are two completley different things o.o because I got y^2= sin(x) + 4 when i did it, but i feel like I did something wrong there.