Find the equation of the plane through (1,1,1) and containing the line which is the intersection of the planes x-y=2 and y-z=1
Can someone explaine to me how this is done
the line of intersecting planes is the cross of their direction vectors
First of all you need to understand how a plane is formed
<1,-1,0> x <0,1,-1> = intersection vector
How did you get that @amistre64?
i pulled of the normals from the plane eqs and crossed them
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okay, so then you did the cross product
yes, cross the normals of the planes given to find the line asked for; then we work from that thing
okay, so the cross product gives us the vector: i+j+k
should i trust you for that? :)
the rest of the question is vague or mistyped
we need to find 2 points on this intersecting line tho
nope that is how it is written on my sample test
find a point that both intersecting planes have in common
x-y=2 and y-z=1 when x=0; y=-2 when y=-2; z=-3?
so the point (0,-2,-3) is on our intersecting line we can use that and another point on the line to create 2 vectors to our (1,1,1) point
line: x= 0+t y=-2+t z=-3+t pick your favorite t
h
h aint a number that we can define a point with
oh i meant 6
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