$$\int\limits_{-6}^{-3}{1 \over x+2}dx$$

Please help with the steps of integration.. I think I can put the -3 and -6 in the equation after you help me integrating it.

Question

$$\int\limits_{-6}^{-3}{1 \over x+2}dx$$

Please help with the steps of integration.. I think I can put the -3 and -6 in the equation after you help me integrating it.

campbell_st · Answer

this is a ln function since the numerator is the derivative of the denominator

f(x) = x + 2   f'(x) = 1

so $$\int\limits_{-6}^{-1} 1/(x+2) dx = \ln(x + 2)$$

so F(x) = ln(x + 2)  Now evaluate by F(-3) - F(-6)

so ln(-1) - ln(-4)

anonymous · Answer

Thank you!

anonymous · Answer

Denyekwe, if you're still there, can you check my new post?

anonymous · Answer

Look at this image and let me know what you think

anonymous · Answer

It makes quite some sense :)

anonymous · Answer

What is confusing about it

anonymous · Answer

It's not confusing, but does it work for every thing like that?

anonymous · Answer

Yes as long as it is in that form. Notice that it is just X not (x^something)

anonymous · Answer

Yes. Thank you!