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5=logbase3(x^2+18) convert to exponential equation,simplify and solve to find two solutions
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put both sides as exoponents to the base 5 3^(5) = 3^logbase3(x^2+18) = 3^(5) = x^(2) + 18
*put both sides as exoponents to the base 3
got it?
Now you can just solve for x as the log_3 is elimenated
\[log_b(x)=y\iff b^y=x\] you should be able to switch back and forth easily. in this case you get \[3^5=x^2+18\]
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