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OpenStudy (anonymous):
OpenStudy (anonymous):
You may see the equation here.
OpenStudy (ash2326):
We have
\[x=\sqrt{7+4\sqrt 3}+\sqrt{7-4\sqrt 3}\]
Let's multiply and divide this by \(\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}\)
we have
\[x=\sqrt{7+4\sqrt 3}+\sqrt{7-4\sqrt 3} \times \frac{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\]
We get
\[x=\frac{{(\sqrt{7+4\sqrt 3})^2 }-(\sqrt{(7-4\sqrt 3})^2 }{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\]
we get
\[x=\frac{7+4\sqrt 3-(7-4 \sqrt 3)}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\]
so we get
\[x=\frac{8\sqrt 3}{\sqrt{7+4\sqrt 3}-\sqrt{7-4\sqrt 3}}\]
OpenStudy (anonymous):
Is this the answer?
OpenStudy (ash2326):
Yeah can't be simplified more
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OpenStudy (anonymous):
How it be made?
OpenStudy (anonymous):
Because the answer is 4.
OpenStudy (anonymous):
Ai Se Eu Te Pego -
OpenStudy (anonymous):
159
OpenStudy (anonymous):
rrsrsrs
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OpenStudy (anonymous):
good
OpenStudy (anonymous):
De onde vc é Elodi?
OpenStudy (anonymous):
quoi
OpenStudy (anonymous):
Vc falou português
OpenStudy (anonymous):
i m from Brazil
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OpenStudy (anonymous):
okk
OpenStudy (anonymous):
or u may send me your link profile
OpenStudy (ash2326):
I got it, Let me show you how this 4
OpenStudy (anonymous):
yes]
OpenStudy (ash2326):
@viniterranova please don't share personal info like facebook id here. Delete it please
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Bye Elodi See u around
i ve got go
OpenStudy (anonymous):
y
OpenStudy (ash2326):
We have
\[x=\sqrt {7+4 \sqrt 3}+\sqrt {7-4 \sqrt 3}\]
Let's square both the sides
we get
\[x^2=(\sqrt {7+4 \sqrt 3})^2+(\sqrt {7-4 \sqrt 3})^2+2\times (\sqrt {7+4 \sqrt 3})\times
(\sqrt {7-4 \sqrt 3})\]
we get
\[x^2=7+4\sqrt 3+7-4\sqrt 3+2 \sqrt{(7^2-(4\sqrt 3)^2}\]
we get
\[x^2=14+2\times \sqrt {49-16\times 3}\]
we get
\[x^2=14+2\times \sqrt 1\]
we get
\[x^2=14+2=16\]
so
\[x=4\]