Question

integrate lnsin2x

Answer 1

do you know the integral for ln x ?

Answer 2

yes

Answer 3

xlnx-x

Answer 4

how did you get that value? using u substitution.

Answer 5

and then use integration by parts

Answer 6

man seems like u need my help lol

Answer 7

u = cos2x

Answer 8

http://openstudy.com/study#/updates/4f525f03e4b019d0ebb02992

Answer 9

Oop, continue Romeo! I'm sorry!

Answer 10

forget it you take over....

Answer 11

u = sin2x --> u' = 2cos2x
(ln sin2x)' = 2cos2x/ sin2x = 2 cot2x

Answer 12

thnks dude

Answer 13

:)

Answer 14

zarkon check the link i posted

Answer 15

from Mathematica V8

\[\int \text{Log}[\text{Sin}[2*x]] \, dx=-x \text{Log}\left[1-e^{4 i x}\right]+x \text{Log}[\text{Sin}[2 x]]+\frac{1}{4} i \left(4 x^2+\text{PolyLog}\left[2,e^{4 i x}\right]\right)\]

Answer 16

thanks zarko