Question

What are the solutions of 6x2 - x - 2 = 0?
Answer

x = 1 over 2 , x = -2 over 3

x = -1 over 2 , x = 2 over 3

x = 1 over 6 , x = -1

x = -1 over 6 , x = 2

Answer 1

factorise the quadratic (2x +1)(3x-2) = 0 then x = -1/2 and 2/3

Answer 2

We have
\[6x^2-x-2=0\]
A standard quadratic equation is of the form
\[ax^2+bx+c=0\]
The roots are given by quadratic formula
\[x=\frac{-b\pm \sqrt {b^2-4ac}}{2a}\]
here we have
a=6, b=-1 and c=-2. Let's substitute the values in quadratic formula to find the roots
\[x=\frac{-(-1)\pm \sqrt {(-1)^2-4\times 6\times (-2)}}{2\times 6}\]
We get
\[x=\frac{1\pm \sqrt{1+48}}{12}\]
we get
\[x=\frac{1\pm \sqrt {49}}{12}=\frac{1\pm 7}{12}\]
we get
\[x= \frac{1+ 7}{12}, \frac{1-7}{12}\]
or
\[x= \frac{8}{12}, -\frac{6}{12}\]
or
\[x=\frac{2}{3}, \frac{1}{2}\]

Answer 3

Sorry made a typo :(
it'd be
\[x=\frac{2}{3}, -\frac{1}{2}\]

Answer 4

lol i was judt about to ask . lol