Write this formula in center form:
x^2 - 14x + 36y^2 - 216g +337 = 0

Question

Write this formula in center form:
x^2 - 14x + 36y^2 - 216g +337 = 0

anonymous · Answer

Can you reprase the question? I am a bit unclear as to what you mean, because I have either never heard the term or have forgotten due to a long period without physical school

anonymous · Answer

It's a question that my pre calc teacher gave me for homework. We've been learning on how to write questions in center form for an ellipse. She asked up for this question to take this standard form and turn it into center form for an ellipse which is $$((x-h)^{2}/ a ^{2}) + ((y-k)^{2}/ b ^{2})$$

anonymous · Answer

Ahh ok, precalc is not my forte, youll have to ask some one else this time :) sorry

anonymous · Answer

thanks anyway! =)

campbell_st · Answer

complete the square for terms in x and then again for terms in y

so x^2 -14x +49 36y^2 -216y + 324      = -337 + 49 + 324

(x - 7)^2 +(6y - 18)^2= 6^2

the centre is (7, 3) and radius = 6 units

anonymous · Answer

how did you get 36y^2 - 216y + 324? where did the 324 come from? dont you have to half 216 and square it?

campbell_st · Answer

given (a + b)^2   the middle term is double the product of a and b

so start my halving -216y. This gives -108y   divide by 6y  (since(6y)^2 = 36y^2)

leaves -18... so the b value is -18...

anonymous · Answer

oooo okay! thank you!