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Mathematics 7 Online
OpenStudy (anonymous):

Solve 5^x/2 = 21

OpenStudy (campbell_st):

start with 5^x = 42 then \[x = \log _{5} 42\] if you don't have base 5 logs then use change of base change to base e logs \[x = \ln(42)/\ln(5) \] x is approx 2.32222 to check use 5^(2.3222) do you get an answer close to 42..?

OpenStudy (anonymous):

5^x = 2 * 21 = 42 -> x = log (5) 42 = 2.32

OpenStudy (campbell_st):

if the problem is \[5^{x/2} = 21\] same process \[x/2 = \log _{5} (21)\] do the change of base and solve for x

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